JEE Advanced 2019 Results @

JEE Advanced 2019 Results @ IIT Roorkey would announce the results of JEE advanced 2019 on June 14. The Optical Response Sheet (ORS) and answer keys will be released on June 4. The students have cleared the JEE Main to be eligible to contest for IITs and NITs in the country. Paper 1 of JEE advanced was held from 9 am to 12 pm while the second paper for JEE Advanced 2019 was held from 2 pm to 5 pm.

JEE Advanced 2019 Results @

JEE Advanced Key dates:
Online Registration begins for JEE (Main) qualified Candidates: May 3, 2019
Online Registration closes: May 9, 2019 17:00 IST
Last date for fee payment of candidates who have successfully completed upto: May 10, 2019
JEE Advance Exam Hall tickets /Admit Cards: May 20, 2019
JEE Advanced Exam date: May 27, 2019
JEE Advanced Exam Answer key: June 4, 2019
JEE Advanced Exam Results : June 14, 2019

JEE Advanced 2019 to be Held on 27-05-2019

The results of the Joint Entrance Examination (JEE) Advanced 2019 will be announced in the second week of June on the official website, the link for which is The Indian Institute of Technology (IIT) will release the results and merit list on June 14.This year, the JEE Advanced 2019 was held in its Computer Based Mode (CBM) on May 27.

JEE Advanced 2019 Results to be out on 14-06-2019

JEE Advanced 2019 has been conducted successfully by IIT Roorkee on May 27, 2019 in Computer Based Test format. JEE Advanced 2019 Result would be released on June 14, 2019 on Students would be getting the notification for their question papers being loaded on the official website. The question papers would be made available to students along with the responses marked by the students. The copy of the responses would be available from May 29 to June 1. Answer Keys would be released on June 4, 2019.

Candidates who have appeared have an option of sending feedback and challenging the answer keys. The option to do so would be available online till 5 pm on June 5, 2019. Based on the answer keys and any objections received, the JEE Advanced 2019 result would be declared on June 14, 2019. Counselling schedule would be shared by JoSAA for admission to various IITs.

How to check JEE Advanced Results 2019:
Step 1: Go to the official website,

Step 2: Click on the relevant link

Step 3: Enter the necessary information

Step 4: After submitting the same, the results will be displayed on the screen

Step 5: Take a printout for future use

Result of JEE (ADV) 2019
Result of JEE (ADV) 2019

Further, the All India Ranks (AIR) of successful candidates will be available through the online portal after the results are declared. Text messages will also be sent to the candidates to their registered mobile numbers. Moreover, individual rank cards will 'NOT' be sent to candidates.

Cut-off marks for the top 20 percentile:
The category-wise cut-off marks for the top 20 percentile are calculated based on the marks scored by the candidates who pass in their respective boards in the particular year
It is reiterated that top 20 percentile cut-off for the academic year 2019 will be considered for the candidates who pass the Class XII (or equivalent) examination in 2019
In case a Board does not provide information about the cut-off for the top 20 percentile, the candidate will have to produce a certificate from the respective board stating that he/she falls within the top 20 percentile of successful candidates. If the candidate fails to do so, then the cut-off marks, in the respective categories, for the CBSE will be used.
According to official data, as many as 1,57,496 appeared for the first paper and 1,55,091 made it to the second paper.

Also, it was reported that over 17,000 candidates did not take up the JEE (Advanced) examination held in two shifts at 573 centers across the nation.

In 2017, over 2.2 lakh candidates appeared for the exam consisted of two papers, i.e. Paper 1 and Paper 2. The JEE Advanced 2019 results were declared on June 11 at 10 am and Sarvesh Mehtani from Chandigarh (Panchkula) obtained the All India Rank (AIR) 1, followed by Pune's Akshat Chugh and Delhi's Ananya Agarwal at the second and third position.

Selection procedure:
"The Joint Entrance Examination (Advanced) 2019 was held in the seven zonal IITs. The performance of a candidate in this examination will form the basis for admission to the Bachelor's, Integrated Master's and Dual Degree programs (entry at the 10+2 level) in all the IITs. The decisions of the JAB 2019 will be final in all matters related to JEE (Advanced) 2019 and admission to IITs," said official website.

About JEE(Advance)2019:
JEE Joint Entrance Examination For Admission to Undergraduate Programs at Indian Institutes of Technology Bhilai, Bhubaneswar, Bombay, Delhi, Dhanbad, Dharwad, Gandhinagar, Goa, Guwahati, Hyderabad, Indore, Jammu, Jodhpur, Kanpur, Kharagpur, Madras, Mandi, Palakkad, Patna, Roorkee, Ropar, Tirupati and Varanasi

JEE Advanced Examination: The Joint Entrance Examination (Advanced) forms the basis for admission to the following programs in Engineering, Science, Architecture and Pharmaceutics in various IITs:
• 4-year Bachelors: B.Tech., B.S., B.Pharm.
• 5-year Bachelors: B.Arch.
• 5-year Dual Degree: B.Tech.-M.Tech., B.S.-M.S.
• 5-year Integrated Masters: M.Tech., M.Sc., M.Pharm Dual Degree.

JEE (Advanced) 2019 will have two papers. Both the papers are compulsory. Each paper is of 3 hour duration and has objective type questions in Physics, Chemistry and Mathematics. The question papers will be either in English or in Hindi. Candidates have to exercise the choice of question paper language at the time of registration. JEE (Advanced) 2019 is being organized any  IITs.

Eligibility Criteria: 
Candidates must fulfill each of the following five criteria for appearing in JEE (Advanced) 2019:
1. Should be among the top 2,20,000 (all categories included) in JEE (Main) 2019.
2. Should be born on or after October 1, 1993. Five years relaxation is given to SC, ST and PwD candidates.
3. Should NOT have appeared in JEE (Advanced) in 2016 or earlier. Candidates who wrote Class Xll in 2016 are eligible if result was declared after June 2016.
4. Should have appeared in Class XII (or equivalent) examination for the first time in 2017 or 2019.
5. Should NOT have accepted admission at any of the llTs earlier.

Reservations are provided to Indian Nationals belonging to certain categories in accordance with the rules of the Government of India and such candidates are declared as qualified in JEE (Advanced) 2019 based on relaxed norms.

Candidates qualified in JEE (Advanced) 2019 will be eligible for admission to the above mentioned academic programs at lITs subject to satisfying at least one of the following two criteria:
1. Must have secured at least 75% aggregate marks in the Class XII (or equivalent) examination. The aggregate marks for SC, ST and PwD candidates should be at least 65%.
2. Must be within the category-wise top 20 percentile of successful candidates in their respective Class XTT (or equivalent) examinations.

Candidates who are eligible for admission will have to participate in joint seat allocation process by filling in their choices of the programs. The schedule of the joint seat allocation will be announced by the Joint Seat Allocation Authority (JoSAA) 2019.

Exam Centers:
 JEE (Advanced) 2019 will be held in select cities and towns in India across seven zones and in a few foreign countries. Every candidate should compulsorily choose three cities I towns from a zone of his I her choice at the time of online registration.

Registration: Candidates declared eligible to appear in JEE (Advanced) 2019 must register online at the JEE (Advanced) web portal by uploading the requisite documents and by paying the registration fee as detailed below:

Examination Fee for Centres in India
Female candidates: Rs.1200
SC, ST, PwD candidates: Rs.1200
All other candidates: Rs. 2400
Late Fee: Rs. 500
For more latest updates visit: in

Examination Fee for Centres in Foreign Countries

Candidates from SAARC countries: USD 135
Candidates from non-SAARC countries: USD 270
Late Fee: USD 80

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